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Redox Reactions Balancing Practice

Advanced Redox Balancing Challenge

Master Redox Balancing

20 Advanced Practice Problems | Acidic & Basic Medium

Instructions: Try to balance these equations on paper first. When you are ready, click the "Submit & Show Detailed Solutions" button at the bottom to reveal the step-by-step answers.

Part I: Acidic Medium

Acidic
1. Permanganate and Oxalate ion
MnO4- + C2O42- → Mn2+ + CO2

Detailed Solution

1. Oxidation: C2O42- → 2CO2 + 2e-
2. Reduction: MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
3. Balance Electrons: Multiply Oxidation by 5 and Reduction by 2.
Final: 2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10CO2 + 8H2O
Acidic
2. Dichromate and Iron(II)
Cr2O72- + Fe2+ → Cr3+ + Fe3+

Detailed Solution

1. Oxidation: Fe2+ → Fe3+ + 1e-
2. Reduction: Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
3. Balance Electrons: Multiply Oxidation by 6.
Final: Cr2O72- + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O
Acidic
3. Arsenic Sulfide and Nitrate (Challenging)
As2S3 + NO3- → H3AsO4 + SO42- + NO

Detailed Solution

1. Oxidation: As2S3 + 20H2O → 2H3AsO4 + 3SO42- + 34H+ + 28e-
2. Reduction: NO3- + 4H+ + 3e- → NO + 2H2O
3. Balance Electrons: Multiply Oxidation by 3 and Reduction by 28.
Final: 3As2S3 + 28NO3- + 4H2O + 10H+ → 6H3AsO4 + 9SO42- + 28NO
Acidic
4. Copper and Nitrate
Cu + NO3- → Cu2+ + NO

Detailed Solution

1. Oxidation: Cu → Cu2+ + 2e-
2. Reduction: NO3- + 4H+ + 3e- → NO + 2H2O
3. Balance Electrons: Multiply Oxidation by 3 and Reduction by 2.
Final: 3Cu + 2NO3- + 8H+ → 3Cu2+ + 2NO + 4H2O
Acidic
5. Iodate and Iodide (Comproportionation)
IO3- + I- → I3-

Detailed Solution

1. Oxidation: 3I- → I3- + 2e-
2. Reduction: 3IO3- + 18H+ + 16e- → I3- + 9H2O
3. Balance Electrons: Multiply Oxidation by 8.
Final: IO3- + 8I- + 6H+ → 3I3- + 3H2O
Acidic
6. Zinc and Nitrate (Formation of Ammonium)
Zn + NO3- → Zn2+ + NH4+

Detailed Solution

1. Oxidation: Zn → Zn2+ + 2e-
2. Reduction: NO3- + 10H+ + 8e- → NH4+ + 3H2O
3. Balance Electrons: Multiply Oxidation by 4.
Final: 4Zn + NO3- + 10H+ → 4Zn2+ + NH4+ + 3H2O
Acidic
7. Thiosulfate and Iodine
S2O32- + I2 → S4O62- + I-

Detailed Solution

1. Oxidation: 2S2O32- → S4O62- + 2e-
2. Reduction: I2 + 2e- → 2I-
3. Balance Electrons: Electrons already balanced (2e-).
Final: 2S2O32- + I2 → S4O62- + 2I-
Acidic
8. Sulfite and Permanganate
SO32- + MnO4- → SO42- + Mn2+

Detailed Solution

1. Oxidation: SO32- + H2O → SO42- + 2H+ + 2e-
2. Reduction: MnO4- + 8H+ + 5e- → Mn2+ + 4H2O
3. Balance Electrons: Multiply Oxidation by 5 and Reduction by 2.
Final: 5SO32- + 2MnO4- + 6H+ → 5SO42- + 2Mn2+ + 3H2O
Acidic
9. Chlorate and Sulfur Dioxide
ClO3- + SO2 → Cl- + SO42-

Detailed Solution

1. Oxidation: SO2 + 2H2O → SO42- + 4H+ + 2e-
2. Reduction: ClO3- + 6H+ + 6e- → Cl- + 3H2O
3. Balance Electrons: Multiply Oxidation by 3.
Final: ClO3- + 3SO2 + 3H2O → Cl- + 3SO42- + 6H+
Acidic
10. Hydrogen Peroxide and Dichromate
H2O2 + Cr2O72- → O2 + Cr3+

Detailed Solution

1. Oxidation: H2O2 → O2 + 2H+ + 2e-
2. Reduction: Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
3. Balance Electrons: Multiply Oxidation by 3.
Final: 3H2O2 + Cr2O72- + 8H+ → 3O2 + 2Cr3+ + 7H2O

Part II: Basic Medium

Basic
11. Phosphorus Disproportionation (Classic)
P4 → PH3 + H2PO2-

Detailed Solution

1. Oxidation: P4 + 8OH- → 4H2PO2- + 4e-
2. Reduction: P4 + 12H2O + 12e- → 4PH3 + 12OH-
3. Balance Electrons: Multiply Oxidation by 3.
Final: P4 + 3OH- + 3H2O → PH3 + 3H2PO2-
Basic
12. Chlorine Disproportionation
Cl2 → Cl- + ClO3-

Detailed Solution

1. Oxidation: Cl2 + 12OH- → 2ClO3- + 6H2O + 10e-
2. Reduction: Cl2 + 2e- → 2Cl-
3. Balance Electrons: Multiply Reduction by 5.
Final: 3Cl2 + 6OH- → 5Cl- + ClO3- + 3H2O
Basic
13. Aluminum and Nitrite
Al + NO2- → AlO2- + NH3

Detailed Solution

1. Oxidation: Al + 4OH- → AlO2- + 2H2O + 3e-
2. Reduction: NO2- + 5H2O + 6e- → NH3 + 7OH-
3. Balance Electrons: Multiply Oxidation by 2.
Final: 2Al + NO2- + OH- + H2O → 2AlO2- + NH3
Basic
14. Chromite and Hypochlorite
Cr(OH)3 + ClO- → CrO42- + Cl-

Detailed Solution

1. Oxidation: Cr(OH)3 + 5OH- → CrO42- + 4H2O + 3e-
2. Reduction: ClO- + H2O + 2e- → Cl- + 2OH-
3. Balance Electrons: Multiply Oxidation by 2 and Reduction by 3.
Final: 2Cr(OH)3 + 3ClO- + 4OH- → 2CrO42- + 3Cl- + 5H2O
Basic
15. Permanganate and Cyanide
MnO4- + CN- → MnO2 + CNO-

Detailed Solution

1. Oxidation: CN- + 2OH- → CNO- + H2O + 2e-
2. Reduction: MnO4- + 2H2O + 3e- → MnO2 + 4OH-
3. Balance Electrons: Multiply Oxidation by 3 and Reduction by 2.
Final: 2MnO4- + 3CN- + H2O → 2MnO2 + 3CNO- + 2OH-
Basic
16. Hydrazine and Chlorate
N2H4 + ClO3- → NO + Cl-

Detailed Solution

1. Oxidation: N2H4 + 4OH- → 2NO + 4H2O + 8e-
2. Reduction: ClO3- + 3H2O + 6e- → Cl- + 6OH-
3. Balance Electrons: Multiply Oxidation by 3 and Reduction by 4.
Final: 3N2H4 + 4ClO3- → 6NO + 4Cl- + 6H2O
Basic
17. Zinc and Nitrate (Zincate formation)
Zn + NO3- → Zn(OH)42- + NH3

Detailed Solution

1. Oxidation: Zn + 4OH- → Zn(OH)42- + 2e-
2. Reduction: NO3- + 6H2O + 8e- → NH3 + 9OH-
3. Balance Electrons: Multiply Oxidation by 4.
Final: 4Zn + NO3- + 7OH- + 6H2O → 4Zn(OH)42- + NH3
Basic
18. Bismuth Hydroxide and Stannite
Bi(OH)3 + SnO22- → SnO32- + Bi

Detailed Solution

1. Oxidation: SnO22- + 2OH- → SnO32- + H2O + 2e-
2. Reduction: Bi(OH)3 + 3e- → Bi + 3OH-
3. Balance Electrons: Multiply Oxidation by 3 and Reduction by 2.
Final: 2Bi(OH)3 + 3SnO22- → 3SnO32- + 2Bi + 3H2O
Basic
19. Ferrate production
Fe(OH)3 + ClO- → FeO42- + Cl-

Detailed Solution

1. Oxidation: Fe(OH)3 + 5OH- → FeO42- + 4H2O + 3e-
2. Reduction: ClO- + H2O + 2e- → Cl- + 2OH-
3. Balance Electrons: Multiply Oxidation by 2 and Reduction by 3.
Final: 2Fe(OH)3 + 3ClO- + 4OH- → 2FeO42- + 3Cl- + 5H2O
Basic
20. Cobalt(II) and Peroxide
Co(OH)2 + H2O2 → Co(OH)3

Detailed Solution

1. Oxidation: Co(OH)2 + OH- → Co(OH)3 + e-
2. Reduction: H2O2 + 2e- → 2OH-
3. Balance Electrons: Multiply Oxidation by 2.
Final: 2Co(OH)2 + H2O2 → 2Co(OH)3

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